Python Practice 14/22

Time calculator

A clock only has 24 hours - the 25th hour is really 1:00 the next day. The % (modulo) operator is exactly the tool for that wraparound: total_minutes % (24 * 60) gives you the minute-of-day no matter how many times past midnight total_minutes has rolled, and total_minutes // (24 * 60) (integer division) tells you how many full days it rolled past.

The trick to this whole problem is working in one flat unit - total minutes since midnight - instead of juggling hours and minutes separately. Convert the start time to minutes, add the duration, then convert back: the hour is minutes // 60 and the minute is minutes % 60.

Your task: write add_duration(start_hour, start_min, duration_min). start_hour is 0-23 and start_min is 0-59 (24-hour time). duration_min is how many minutes to add. Return a tuple (end_hour, end_min, days_later), where days_later is 0 if the end time lands on the same day, 1 if it rolls past one midnight, and so on.

You'll practice:

Converting hours and minutes into one flat total, and back
Using // and % together to wrap a value and count how many times it wrapped

# Write add_duration(start_hour, start_min, duration_min):
# returns (end_hour, end_min, days_later) after adding duration_min
# minutes to the start time, wrapping at 24 hours.
def add_duration(start_hour, start_min, duration_min):
    pass